SOLUTION: Find three consecutive integers such that twice the smallest is 12 more than the largest

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Question 908747: Find three consecutive integers such that twice the smallest is 12 more than the largest
Answer by CubeyThePenguin(3113) About Me  (Show Source):
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consecutive integers: (x-1), x, (x+1)

2(x-1) = (x+1) + 12
2x-2 = x+13
x = 15

The integers are 14, 15, and 16.