SOLUTION: I have NO clue where to start.
Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a<b, then ac<bc.
IF you can solve this I will be fore
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-> SOLUTION: I have NO clue where to start.
Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a<b, then ac<bc.
IF you can solve this I will be fore
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Question 90874: I have NO clue where to start.
Give a counterexample to show the statement is not always true for real numbers a, b, & c. If a
IF you can solve this I will be forever grateful. Answer by throwabunny(3) (Show Source):
You can put this solution on YOUR website! I guess if you had 4 for a, and 5 for b, and multiplied them by -1, it wouldn't work.
Something with negatives in it.
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