SOLUTION: 2cos(5 theta) + square root of 3 = 0 I have tried making theta equal 5theta and then I made, 2cos theta + square root of 3 = 0 to get, cos= -square root of 3 all over 2. I

Algebra ->  Trigonometry-basics -> SOLUTION: 2cos(5 theta) + square root of 3 = 0 I have tried making theta equal 5theta and then I made, 2cos theta + square root of 3 = 0 to get, cos= -square root of 3 all over 2. I      Log On


   

Question 908501: 2cos(5 theta) + square root of 3 = 0

I have tried making theta equal 5theta and then I made,
2cos theta + square root of 3 = 0 to get,
cos= -square root of 3 all over 2.
I went to the unit circle and looked at where cos = -square root of 3 all over 2 and that is 5 pie/6 and 7 pie/6.
Now I do not kknow what to do next or if I even started the answer right?



Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
2cos(5 theta) + square root of 3 =0
2cos%285theta%29%2Bsqrt%283%29=0
cos%285theta%29=-sqrt%283%29%2F2
5theta=5π/6,7π/6
theta=5π/30,7π/30