|
Question 908408: . Find the equation of a line described as follows and express your answer in point-slope form, slope-intercept form, and standard form
Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through the point (-4, -6)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the equation of a line described as follows and express your answer in point-slope form, slope-intercept form, and standard form
Find the equation of the line perpendicular to the line y+3=3(x-5) that passes through the point (-4, -6)
***
y+3=3(x-5)
slope,m=3
slope of perpendicular line=-1/3 (negative reciprocal
..
slope-intercept form: y=m+b, m=slope, b=y-intercept
y=-x/3+b
solve for b using coordinates of given point (-4,-6) on the line
-6=-(-4)/3+b
-18=4+3b
b=-22/3
y=-x/3-22/3 (slope-intercept form)
..
Point-slope form:(y1-y2)=m(x1-x2)
(y-(-6))=m(x-(-4))
(y+6)=-(1/3)(x+4)
..
Standard form:ax+by=c
y=-(x/3-22/3
3y=-x-22
x+3y=-22
|
|
|
| |
