Question 907910: The probability that a part produced by a certain factory's assembly line will be defective is 0.026. Find the probabilities that in a run of 42 items, the following results ware obtained:
A. The probabilty that exacly 3 parts will be defective is:
B. The probabilty that no more than 2 parts will be defective is:
C. The probability that at least 1 part will be defective is:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! p(def) = .026 , n = 42
P(x=3) = binompdf(42, .026, 3)
P(x > 2) = 1 - P(x≤1) = 1 - binomcdf(42, .026, 1)
P(at least one) = 1 - P(none) = 1 - binompdf(42, .026, 0)
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