Question 907889: I am trying to figure this question out.
Two trains at the same time from which were 360 miles apart and traveled toward each other. The rate of the fast train exceeded the rate of the slow train by 10 mph. At the end of 2 hours, the trains were still 120 miles apart. Find the rate of each train.
So far I have done this,
r1=10 + r2
t=2
d1+d2=360 - 120=240
but I am still so confused I don't even understand how I got that. If someone could please show me how to actually set the problem up to figure it out. Thank you.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Two trains at the same time from which were 360 miles apart and traveled toward each other.
The rate of the fast train exceeded the rate of the slow train by 10 mph.
At the end of 2 hours, the trains were still 120 miles apart.
Find the rate of each train.
:
You have the right idea!
:
let s = the speed of the slower train
then
(s+10) = the speed of the faster train
:
This means that the total distance traveled by the two trains: 360-120 = 240
:
write a distance equation: dist = time * speed
:
slow train dist + fast train dist = 240
2s + 2(s+10) = 240
:
You should be able to do this now
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