SOLUTION: Elizabeth Suco and her friend Harold Tanner are riding their bicycles in a fundraiser for charity. Harold leaves the starting point at 7:00 AM and rides at 15 miles per hour. Eliz

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Question 907728: Elizabeth Suco and her friend Harold Tanner are riding their bicycles in a fundraiser for charity. Harold leaves the starting point at 7:00 AM and rides at 15 miles per hour. Elizabeth leaves the starting point at 7:30 AM and rides at 18 miles per hour.
How long after Elizabeth leaves the starting point will she catch up?
How far from the starting point will they be?
Found 2 solutions by lwsshak3, mananth:
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
Elizabeth Suco and her friend Harold Tanner are riding their bicycles in a fundraiser for charity. Harold leaves the starting point at 7:00 AM and rides at 15 miles per hour. Elizabeth leaves the starting point at 7:30 AM and rides at 18 miles per hour.How long after Elizabeth leaves the starting point will she catch up? How far from the starting point will they be?
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let x=Elizabeth's travel time
x+.5=Harolds's travel time
speed*travel time=distance (equal for both)
..
15(x+.5)=18x
15x+7.5=18x
3x=7.5
x=2.5
18x=45
How long after Elizabeth leaves the starting point will she catch up? 2.5 hrs
How far from the starting point will they be? 45 miles

Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website!
the distance traveled by both is same when one catches up with the other.
Let them meet at distance x
Suco speed= 15 mph , starts at 00:00 am
Tanner speed= 18 mph starts at 07:30 am

Time difference between the starting of the two= 0.50 hours

Time taken by Suco = X / 15
Time taken by Tanner = X / 18

X / 15 - X / 18 = 0.5

LCD - 90
Multiply equation by 90 90

6 x - 5 x = 45
1 x = 45
/ 1
x= 45 miles
Tanner speed= 18 mph
Distance = 45 miles
Time taken = 45 / 18
Time taken to catch up = 2.5 hour