SOLUTION: SOLVE THE SYSTEM BY ADDING OR SUBTITUTION 3X+6y=0 x=2/3 solve the sysem by adding 5x-4y+-12 x+5y=15

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Question 90772: SOLVE THE SYSTEM BY ADDING OR SUBTITUTION
3X+6y=0
x=2/3
solve the sysem by adding
5x-4y+-12
x+5y=15
Answer by malakumar_kos@yahoo.com(315) About Me  (Show Source):
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SOLVE THE SYSTEM BY ADDING OR SUBTITUTION
3X+6y=0
x=2/3
solve the sysem by adding
5x-4y+-12
x+5y=15

1) x = 2/3.......(1)
3x+6y = 0.....(2)
substitute for x in (2)
3*2/3+6y = 0
6y = -2 or y = -1/3
The solution is (2/3, -1/3)


2)5x-4y = 12.......(1)
x+5y = 15.......(2)
multiply (2) by -5 and add to (1)
-5x-25y = -75
5x-4y = 12
-29y = -63
y = 63/29
To find x substitute for y in (2)
x = 15-5y = 15-5(63/29) =( 435-315)/29 = 120/29
The solution is (120/29,63/29)