SOLUTION: Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player?
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-> SOLUTION: Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player?
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Question 907695: Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Eighty one percent of U.S. households have DVD players. Choose 6 households at random. What is the probability that at least one does not have a DVD player?
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P(at least one does not have) = 1 - P(all have a DVD player)
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P(at least one) = 1 - (0.81)^6 = 1 - 0.7176 = 0.2824
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Cheers,
Stan H.
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