SOLUTION: The load L that a helical spring can support varies directly as the cube of its wire
diameter d and inversely as its coil diameter D. A spring for which d = 0.1 cm and D =
0.9 cm
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-> SOLUTION: The load L that a helical spring can support varies directly as the cube of its wire
diameter d and inversely as its coil diameter D. A spring for which d = 0.1 cm and D =
0.9 cm
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Question 907693: The load L that a helical spring can support varies directly as the cube of its wire
diameter d and inversely as its coil diameter D. A spring for which d = 0.1 cm and D =
0.9 cm can support 50 N. What is the coil diameter of a similar spring that supports
78.5 N and for which d = 0.2 cm?
You can put this solution on YOUR website! The load L that a helical spring can support varies directly as the cube of its wire diameter d and inversely as its coil diameter D.
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L = kd^3/D
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Solve for "k" using "A spring for which d = 0.1 cm and D = 0.9 cm can support 50 N."
50 = k*0.1^3/0.9
45 = 0.001k
k = 45000
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Equation:
L = 45000*d^3./D
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What is the coil diameter of a similar spring that supports
78.5 N and for which d = 0.2 cm?
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78.5 = 45000*0.2^3/D
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D = 45000*0.2^3/78.5
D = 4.59 cm
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Cheers,
Stan H.
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