SOLUTION: Is it possible for x = -2 to be in the Domains of the functions a) R(x) = (3x^3 - 5x + 6)/(x+2) b) H(x) = {{{ sqrt (x+1) }}} Explain why or why not for each function. What

Algebra ->  Functions -> SOLUTION: Is it possible for x = -2 to be in the Domains of the functions a) R(x) = (3x^3 - 5x + 6)/(x+2) b) H(x) = {{{ sqrt (x+1) }}} Explain why or why not for each function. What       Log On


   

Question 907520: Is it possible for x = -2 to be in the Domains of the functions
a) R(x) = (3x^3 - 5x + 6)/(x+2)
b) H(x) = +sqrt+%28x%2B1%29+
Explain why or why not for each function.
What are the Domains of the functions R(x) and H(x)? If required, use inf.for infinity.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Is it possible for x = -2 to be in the Domains of the functions
a) R(x) = (3x^3 - 5x + 6)/(x+2)
If x=-2, denominator=0, making function undefined.
x≠-2
domain: (-inf,-2) U (2,inf)
b) H(x) = +sqrt+%28x%2B1%29+
If x=-2, radican becomes <0, which is not allowed by definition.
x≠-2
domain: (-inf,-2) U (2,inf)