SOLUTION: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution?

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Question 907385: How many liters of a 60% acid solution must be mixed with a 25% acid solution to get 315L of a 50% acid solution?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x 60% amount
.60x + .25(315L - x) = .50(315L)
x = .25(315L)/.35