Question 907384: how many liters of a 70% alcohol solution must be mixed with 40 liters of a 90% solution to get a 80% solution? Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! x amount of 70% solution
.70x + .90(40L) = .80(40L + x)
.10(40L)/.10 = x = 40L, amount of 70% solution