SOLUTION: find the smallest of three consecutive even integers such that three times the first integer is eight more than the sum of the second and the third

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Question 907037: find the smallest of three consecutive even integers such that three times the first integer is eight more than the sum of the second and the third
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive even integers: (x-2), x, (x+2)

3(x-2) = 8 + (x + (x+2))
3x - 6 = 8 + 2x + 2
x = 16

The integers are 14, 16, and 18.