SOLUTION: How many liters of 60% alcohol solution and 20% alcohol solution must be mixed to obtain 16 liters of 50% alcohol solution?

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Question 906807: How many liters of 60% alcohol solution and 20% alcohol solution must be mixed to obtain 16 liters of 50% alcohol solution?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
a+b=16,
0.6*a+0.2*b=0.5*16
a=16-b
0.6*(16-b)+0.2*b=8
9.6-0.6b+0.2*b=8
-0.4*b=-1.6
b=4
a=16-b
a=12 liter at 60%
b=4 liter at 20%
check
0.6*12+0.2*4=0.5*16
7.2+0.8=8
8=8
ok