SOLUTION: The owner of a candy store wants to mix some peanuts worth $2 per pound, some cashews worth $9 per pound, and some Brazil nuts worth $7 per pound to get 50 pounds of a mixture that

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Question 906774: The owner of a candy store wants to mix some peanuts worth $2 per pound, some cashews worth $9 per pound, and some Brazil nuts worth $7 per pound to get 50 pounds of a mixture that will sell for $4.70 per pound. She uses 20 fewer pounds of cashews than peanuts. How many pounds of each did she use?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
p, c, b for the poundages of peanuts, cashews, brazil nuts.

2p%2B9c%2B7b=%284.70%29%2A50, account for the cost of 50 pound mixture
p%2Bc%2Bb=50, account for amount of mixture
c=p-20, the described relationship between two of the nuts

Simplify the system by first substituting for c, and simplify the two remaining equations which are now using only variables b and p.
Solve the system.