SOLUTION: Two alcohol solutions are available: one containing 12% alcohol, and the other containing 37% alcohol. How many liters of the 37% alcohol solution -the second solution- must be use
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Question 906638: Two alcohol solutions are available: one containing 12% alcohol, and the other containing 37% alcohol. How many liters of the 37% alcohol solution -the second solution- must be used in order to obtain 32 liters of a mixture that contains 28% alcohol?
Round-off your answer to one decimal place. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! a+b=32,
0.37*a+0.12*b=0.28*32
a=32-b
0.37*(32-b)+0.12*b=8.96
11.84-0.37b+0.12*b=8.96
-0.25*b=-2.88
b=11.52
a=32-b
a=20.48 liter at 37%
b=11.52 liter at 12%
rounded
a=20.5 liter at 37%
b=11.5 liter at 12%
check
0.37*20.48+0.12*11.52=0.28*32
7.5776+1.3824=8.96
8.96=8.96
ok
