SOLUTION: 9x^2 + 4y^2 + 18x - 16y = 1 I have a problem when solving this equation to get it in the standard form. I got (9(x+1)^2)/26+(2(y-2)^2)/13=1 as the answer which I dont think th

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 9x^2 + 4y^2 + 18x - 16y = 1 I have a problem when solving this equation to get it in the standard form. I got (9(x+1)^2)/26+(2(y-2)^2)/13=1 as the answer which I dont think th      Log On


   

Question 906591: 9x^2 + 4y^2 + 18x - 16y = 1
I have a problem when solving this equation to get it in the standard form.
I got (9(x+1)^2)/26+(2(y-2)^2)/13=1 as the answer which I dont think that it is the correct answer.
What is the actual answer or solution for this question? Thank you.
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2 + 4y^2 + 18x - 16y = 1
9x^2 + 18x + 4y^2 - 16y = 1
9*(x^2 + 2x) + 4*(y^2 - 4y) = 1
9*(x^2 + 2x + 1) -9 + 4*(y^2 - 4y + 4) -16 = 1
9*(x^2 + 2x + 1) + 4*(y^2 - 4y + 4) = 26
(x+1)^2/4 + (y-2)^2/9 = 13/18
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It's not solving, it's not a solution.
It's just put into standard form.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2 + 4y^2 + 18x - 16y = 1
I have a problem when solving this equation to get it in the standard form.
I got (9(x+1)^2)/26+(2(y-2)^2)/13=1 as the answer which I dont think that it is the correct answer.
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9x^2 + 4y^2 + 18x - 16y = 1
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9(x^2 + 2x + 1) + 4(y^2 -4y + 4) = 1+9 + 16
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(x+1)^2/(9/26) + (y-2)^2/(4/26) = 1
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Cheers,
Stan H.
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