SOLUTION: Jane leaves her house and drives in a straight line at a speed of 40 mph. Her speed on the return trip is 50 mph. The trip back home takes 10 minutes less than the outbound trip. W

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Question 906519: Jane leaves her house and drives in a straight line at a speed of 40 mph. Her speed on the return trip is 50 mph. The trip back home takes 10 minutes less than the outbound trip. What was Jane's total travel time in hours? Assume both trips are in a straight line. Give your final answer as a simplified fraction.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
40*t=50*(t+-10/60)
40*t=50*t+-500/60
40*t=50*t+-500/60
500/60=50+40*t
500/60=10*t
50/60=t
5/6=t
t=5/6 hours
t=0.83333333 hours
distance =40*0.83333333=33.3333333 miles
distance =50*0.66666667=33.3333333 miles