SOLUTION: Write an equation in slope-intercept form for the line form that is perpendicular to 5x + 3y = 18 and passes through the origin.

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Question 906306: Write an equation in slope-intercept form for the line form that is perpendicular to 5x + 3y = 18 and passes through the origin.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
the standard slope-intercept form for an equation of a line is
y+=+highlight_green%28m%29x+%2B+highlight%28b%29 where m is the slope and b the y-intercept.
5x + 3y = 18 0r y = (-5/3)x + 6, m = (-5/3)
New line: m = ++highlight_green%283%2F5%29+ as %28-5%2F3%29%283%2F5%29+=+-1 (I think of 3/5 as the negative reciprocal of -5/3)
***Using point-slope form, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29P(0,0)
y-0 = (3/5)(x-0)
y = (3/5)x in slope-intercept form