SOLUTION: This is a rather odd one I'm not even sure if I put this in the right area.. It says that I have to solve for Y and C in the equation Y = C + I + G C = a + bY It gives the

Algebra ->  Linear-equations -> SOLUTION: This is a rather odd one I'm not even sure if I put this in the right area.. It says that I have to solve for Y and C in the equation Y = C + I + G C = a + bY It gives the       Log On


   



Question 905846: This is a rather odd one I'm not even sure if I put this in the right area..
It says that I have to solve for Y and C in the equation
Y = C + I + G
C = a + bY
It gives the answer in the answer key but I don't know how they got it. It provides no help for me whatsoever. I looked through the entire chapter of the book twice

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
You have two equations and two unknowns.
It should be solvable.
Use one equation and substitute into the other equation.
C=a%2Bb%28C%2BI%2BG%29
C=a%2BbC%2BbI%2BbG
C-bC=a%2BbI%2BbG
C%281-b%29=a%2Bb%28I%2BG%29
C=%28a%2Bb%28I%2BG%29%29%2F%281-b%29
Then,
Y=%28a%2Bb%28I%2BG%29%29%2F%281-b%29%2BI%2BG