SOLUTION: Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 6 mph faster than the east bound cyclist. After 5 hours they ar
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Question 905738: Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 6 mph faster than the east bound cyclist. After 5 hours they are 240 miles apart. How fast is each cyclist riding?
You can put this solution on YOUR website! Two cyclists leave a city at the same time, one going east and the other going west. The west bound cyclist bikes at 6 mph faster than the east bound cyclist. After 5 hours they are 240 miles apart. How fast is each cyclist riding?
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let x=speed of slower eastbound cyclist
x+6=speed of faster westbound cyclist
distance=travel time*speed
..
5x+5(x+6)=240
5x+5x+30=240
10x=210
x=21
x+6=27
speed of slower eastbound cyclist=21 mph
speed of faster westbound cyclist=27 mph
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