Question 905608: 6(-7 + 6i)(-4 + 2i)
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! 6(-7 + 6i)(-4 + 2i)
6[(-7 + 6i)(-4 + 2i)]
6[-7(-4 + 2i) + 6i(-4 + 2i)]
6[-7(-4) - 7(2i) + 6i(-4) + 6i(2i)]
6(28 - 14i - 24i + 12i^2)
6(28 - 14i - 24i + 12(-1))
6(28 - 14i - 24i - 12)
6(16 - 38i)
6(16) + 6(-38i)
96 - 228i
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So, 6(-7 + 6i)(-4 + 2i) = 96 - 228i and it is in the form a+bi where a = 96 and b = -228
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