SOLUTION: Jesse and Larry entered a pie eating contest. Jesse ate 5 less than twice as many pies as Larry. They ate a total of 16 pies. How many pies did each eat?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Jesse and Larry entered a pie eating contest. Jesse ate 5 less than twice as many pies as Larry. They ate a total of 16 pies. How many pies did each eat?      Log On


   



Question 905559: Jesse and Larry entered a pie eating contest. Jesse ate 5 less than twice as many pies as Larry. They ate a total of 16 pies. How many pies did each eat?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
x amount of pies Larry ate
Jesse + Larry
(2x-5) + x = 16
3x = 21
x = 7, amount of pies Larry ate. Jesse ate 9 14-5%29
And... checking
sum is 16