SOLUTION: I need to find the product of this problem:(2x-5)^2. Thank you for your help!!

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Question 90554: I need to find the product of this problem:(2x-5)^2. Thank you for your help!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Rewrite %282x-5%29%5E2 as %282x-5%29%282x-5%29

When you FOIL, you multiply the terms in this order:
F-First (i.e. you multiply the first terms in each parenthesis which in this case are 2x and 2x)
O-Outer (i.e. you multiply the outer terms in each parenthesis which in this case are 2x and -5)
I-Inner (i.e. you multiply the inner terms in each parenthesis which in this case are -5 and 2x)
L-Last (i.e. you multiply the last terms in each parenthesis which in this case are -5 and -5)


So lets multiply the first terms:
2x%2A2x=4x%5E2 multiply 2x and 2x to get 4x%5E2



So lets multiply the outer terms:
2x%2A-5=-10x multiply 2x and -5 to get -10x



So lets multiply the inner terms:
-5%2A2x=-10x multiply -5 and 2x to get -10x



So lets multiply the last terms:
-5%2A-5=25 multiply -5 and -5 to get 25

Now lets put all the multiplied terms together
4x%5E2-10x-10x%2B25

Now combine like terms

4x%5E2-20x%2B25

So the expression

%282x-5%29%282x-5%29

FOILs to:

4x%5E2-20x%2B25