SOLUTION: Hi!We started learning how to translate word problems into actual equations using the consecutive integers(odd/even) and im having problems getting the wording correct heres the pr

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Hi!We started learning how to translate word problems into actual equations using the consecutive integers(odd/even) and im having problems getting the wording correct heres the pr      Log On


   

Question 905461: Hi!We started learning how to translate word problems into actual equations using the consecutive integers(odd/even) and im having problems getting the wording correct heres the problem and what ive done so far. thanks for you time!
Find three consecutive integers such that three times the first one is eight more than the sum of the last two integers
1.X
2.X+1
3.X+2
3X=8(X+1+X+2)
3X=8(2X+3)
3X=16X+24
24=16X-3X
24=13X
24/13=13X/13
X=24/13?
Answer by JoelSchwartz(130) About Me  (Show Source):
You can put this solution on YOUR website!
Where you made your mistake was when you multiplied eight by the sum of the last two integers. Eight more than the sum of the last two integers is equal to 8+x+1+x+2 and that is equal to three times the first integer.
3x=8+x+1+x+2
3x=11+2x
x=11
33=11+22