SOLUTION: hi can you help me figure this out ;Factor using the ac-method.

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Question 905066: hi can you help me figure this out ;Factor using the ac-method.
Found 2 solutions by jim_thompson5910, richwmiller:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

108x%5E2%2B63xy%2B9y%5E2 Start with the given expression.


9%2812x%5E2%2B7xy%2By%5E2%29 Factor out the GCF 9.


Now let's try to factor the inner expression 12x%5E2%2B7xy%2By%5E2


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Looking at the expression 12x%5E2%2B7xy%2By%5E2, we can see that the first coefficient is 12, the second coefficient is 7, and the last coefficient is 1.


Now multiply the first coefficient 12 by the last coefficient 1 to get %2812%29%281%29=12.


Now the question is: what two whole numbers multiply to 12 (the previous product) and add to the second coefficient 7?


To find these two numbers, we need to list all of the factors of 12 (the previous product).


Factors of 12:
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 12.
1*12 = 12
2*6 = 12
3*4 = 12
(-1)*(-12) = 12
(-2)*(-6) = 12
(-3)*(-4) = 12

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 7:


First NumberSecond NumberSum
1121+12=13
262+6=8
343+4=7
-1-12-1+(-12)=-13
-2-6-2+(-6)=-8
-3-4-3+(-4)=-7



From the table, we can see that the two numbers 3 and 4 add to 7 (the middle coefficient).


So the two numbers 3 and 4 both multiply to 12 and add to 7


Now replace the middle term 7xy with 3xy%2B4xy. Remember, 3 and 4 add to 7. So this shows us that 3xy%2B4xy=7xy.


12x%5E2%2Bhighlight%283xy%2B4xy%29%2By%5E2 Replace the second term 7xy with 3xy%2B4xy.


%2812x%5E2%2B3xy%29%2B%284xy%2By%5E2%29 Group the terms into two pairs.


3x%284x%2By%29%2B%284xy%2By%5E2%29 Factor out the GCF 3x from the first group.


3x%284x%2By%29%2By%284x%2By%29 Factor out y from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%283x%2By%29%284x%2By%29 Combine like terms. Or factor out the common term 4x%2By


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So 9%2812x%5E2%2B7xy%2By%5E2%29 then factors further to 9%283x%2By%29%284x%2By%29


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Answer:


So 108x%5E2%2B63xy%2B9y%5E2 completely factors to 9%283x%2By%29%284x%2By%29.


In other words, 108x%5E2%2B63xy%2B9y%5E2=9%283x%2By%29%284x%2By%29.


Note: you can check the answer by expanding 9%283x%2By%29%284x%2By%29 to get 108x%5E2%2B63xy%2B9y%5E2.

Answer by richwmiller(17219) About Me  (Show Source):