SOLUTION: Suppose that 6 men in 100 are colorblind, while 22 women in 10,000 are colorblind. Compute the probability that a colorblind individual is male. Assume that the population contains

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose that 6 men in 100 are colorblind, while 22 women in 10,000 are colorblind. Compute the probability that a colorblind individual is male. Assume that the population contains      Log On


   

Question 904966: Suppose that 6 men in 100 are colorblind, while 22 women in 10,000 are colorblind. Compute the probability that a colorblind individual is male. Assume that the population contains an equal number of males and females. Round your answer to two decimal places.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Re TY, my thoughts 6/100 = 600/10,000 men are colorblind and for women given 22/10,000

Or 622/10,000 = .0622 of the population, in general, are colorblind

P(A|B) = P(A and B)/P(B)

P(male|colorblind) = .06/.0622) = .9646  0r 96.46% chance colorblind individual is male

common sense tell the number say: if colorblind most likely a male.