SOLUTION: Cosx=4/5 then tanx/[1+(tanx)^2]
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Question 904892
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Cosx=4/5 then tanx/[1+(tanx)^2]
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lwsshak3(11628)
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Cosx=4/5 then tanx/[1+(tanx)^2]
Working with a 3-4-5 right triangle
tanx=3/4
tanx/[1+(tanx)^2]
=(3/4)(1+(3/4)^2)
=(3/4)+(3/4)^3)
=3/4+27/64
=48/64+27/64
=75/64