SOLUTION: q^2-4/q^2-4+4

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Question 90477This question is from textbook
: q^2-4/q^2-4+4 This question is from textbook

Answer by kamallohia(18) About Me  (Show Source):
You can put this solution on YOUR website!
q^2-4/q^2-4+4=0
Just put q^2=x and rewrite the equation as
x-(4/x-4)+4=0
that is, x^2-20=0
=> x^2=20 and squaure root both sides yields
x= 20^0.5
and q=20^0.25