SOLUTION: Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.
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-> SOLUTION: Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.
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Question 904766
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Find three consecutive integers such that the product of the first and the third integers exceeds 4 times the second by 20.
Answer by
CubeyThePenguin(3113)
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consecutive integers: (x-1), x, (x+1)
(x-1)(x+1) = 4x + 20
x^2 - 1 = 4x + 20
x^2 - 4x - 21 = 0
(x + 3)(x - 7) = 0
The integers could be {-4, -3, -2} or {6, 7, 8}.
