SOLUTION: A bus enters a highway driving 55 mph. A car enters the highway at the same place 1/4 of an hour later and drives 70 mph in the same direction. From the time the car enters the hig
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Question 904551: A bus enters a highway driving 55 mph. A car enters the highway at the same place 1/4 of an hour later and drives 70 mph in the same direction. From the time the car enters the highway, how long will it take the car to pass the bus? Found 2 solutions by ewatrrr, richwmiller:Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! d = rt
t the bus time
55t = 70(t-.25)
55t = 70t - 70*.25
70*.25/15 = 70/60 = 1 1/6 hr, time bus traveled
car traveled 7/6 - 1/4 = 11/12 hr
You can put this solution on YOUR website! gaining speed 70 -55= 15 mph
headstart 55*0.25 =13.75 miles
time to catch up 13.75/15=0.91666667 hours
time to catch up =55 minutes
algebraic solution
55(t+0.25)=70t
55t+13.75=70t
13.75=70t-55t
13.75=15t
0.91666667=t
distance to meeting 0.91666667*70=64.1666667 miles