Question 90455This question is from textbook elementary algebra
: solve by addition method:
x/3-y/2=-5/6
x/5-y/3=-3/5
This question is from textbook elementary algebra
Answer by malakumar_kos@yahoo.com(315)   (Show Source):
You can put this solution on YOUR website!
solve by addition method:
x/3-y/2=-5/6
x/5-y/3=-3/5
x/3-y/2 = -5/6 l.c.m for 2,3 = 6 multiply each term by 6 we get
2x-3y = -5......(1)
x/5-y/3 =-3/5 l.c.m for 3,5 = 15 multiply each term by 15 we get
3x-5y =-9........(2)
-3(2x-3y = -5) (multiply eq'n (1) by -3)
-6x+9y = 15......(3)
2(3x-5y=-9) (multiply eq'n (2) by 2)
6x-10y = -18.....(4)
adding eq'n(3) and eq'n (4) we get -y =-3 or y =3
substitute the value of y in eq'n(3) -6x+9*3 = 15
-6x+27-15 = 0
12 = 6x or x = 12/6 = 2
The required solution is x = 2 and y = 3
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