SOLUTION: Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have? Please help me! I have been stuck on this prob

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have? Please help me! I have been stuck on this prob      Log On

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Question 904491: Jo has 37 coins (all nickels, dimes, and quarters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have?
Please help me! I have been stuck on this problem for the last half an hour. Also, please show me how to set up the equation. Thanks in advanced.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
n+d+q=37,
5n+10d+25q=550,
q-n=4
1,1,1,37
5,10,25,550
-1,0,1,4
(12,9,16)
12n 60
9d 90
16q 400