SOLUTION: The sum of three consecutive odd integers is 21 more than twice of the smallest of the three integers
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Question 904335
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The sum of three consecutive odd integers is 21 more than twice of the smallest of the three integers
Answer by
CubeyThePenguin(3113)
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consecutive odd integers: (x-2), x, (x+2)
(x-2) + x + (x+2) = 21 + 2(x-2)
3x = 21 + 2x - 4
x = 17
The integers are 15, 17, and 19.
