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Solve the system by substitution.
3x – y = –7
x + y = –9
3x-y = -7.........(1)
x+y = -9..........(2)
From eq'n (2) we get x = -9-y
substituing for x in eq'n (1) we get 3(-9-y)+y = -7
-27-3y+y = -7
-2y = -7+27
y = 20/-2 = -10
substituting the value of y in eq'n (2),we get x-10 = -9
x = 10-9 = 1
The values of x = 1 and y = -10 are the required solution for the given eq'n
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