SOLUTION: A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second. Its height measured in feet is given in terms of tim

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Question 904236: A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second.
Its height measured in feet is given in terms of time t, measured in seconds by the equation
h = -16 t^2 + 117 t + 376

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second.
Its height measured in feet is given in terms of time t, measured in seconds by the equation
h = -16 t^2 + 117 t + 376
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That seems reasonable.
Don't put spaces after the coefficients, tho.
h = -16t^2 + 117t + 376