Question 904234: Find the value of k so that the line containing the points (-3,6) and (4,k) is perpendicular to the line containing the points (-9,-4) and (4,-1).
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! the slopes of the two lines will have -1 as their product
-9,-4,4,-1
slope 3/13
perpendicular slope -13/3
-3,6,4,k
x-3-4=-7
6-k
(6-k)/-7=-13/3
3*(6-k)=13*7
18-3k=91
-3k=109
k=-109/3
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