SOLUTION: find exact values of s given interval [0, 2pi) ; sin s= - square root 3/ -2

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Question 904160: find exact values of s given interval [0, 2pi) ; sin s= - square root 3/ -2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find exact values of s given interval [0, 2pi) ; sin s= - square root 3/ -2
sin%28s%29=-sqrt%283%29%2F-2=sqrt%283%29%2F2
s=π/3, 2π/3 (in quadrants I and II where sin>0