SOLUTION: if you can buy b bananas for n nickels, how many bananas can you buy for d dimes and q quarters? - Here is what I tried: b=5n b=20n + 25q I thought this would be a system o

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Question 904056: if you can buy b bananas for n nickels, how many bananas can you buy for d
dimes and q quarters?
- Here is what I tried:
b=5n
b=20n + 25q
I thought this would be a system of equations problem, but I am not sure how to proceed.
Here are the answer choices:
a) (b/n)*(2d+5q)
b) (b(d+q))/n
c) (b/n)*(10d+25q)
d) (10d+25q)/bn
e) (d+q)/bn

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
["b=5n" is wrong because you can't set bananas equal to money.]



you can buy b bananas for n nickels
Therefore b bananas sell for 5n cents

Divide the bananas and the money both by b:

Therefore b%2Fb or 1 banana sells for 5n%2Fb cents

How many bananas can you buy for d dimes and q quarters?
Suppose the answer is x bananas:

Since one banana sells for 5n%2Fb cents, 
x bananas sell for 5n%2Ax%2Fb cents.

Now we see how much money is d dimes and q quarters:

d dimes is 10d cents and q quarters is 25q cents
So d dimes and q quarters is 10d+25q cents.
We can factor out 5, 5(2d+5q)

Set that equal to 5(2d+5q)

5n%2Ax%2Fb%22%22=%22%225%282d%2B5q%29

Multiply both sides by b to clear of fractions:

5n%2Ax%22%22=%22%225b%282d%2B5q%29

Divide both sides by 5n

x%22%22=%22%22%285b%282d%2B5q%29%29%2F%285n%29

Cancel the 5's

x%22%22=%22%22%28b%282d%2B5q%29%29%2Fn

That's the same as %28b%2Fn%29%2A%282d%2B5q%29, choice (a)

Edwin