SOLUTION: what is the area of a rectangle whose sides are twice as long as the sides of a smaller rectangle whose area is 17cm^2?

Algebra ->  Rectangles -> SOLUTION: what is the area of a rectangle whose sides are twice as long as the sides of a smaller rectangle whose area is 17cm^2?      Log On


   



Question 903940: what is the area of a rectangle whose sides are twice as long as the sides of a smaller rectangle whose area is 17cm^2?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
.
smaller: A = Lw = 17cm^2 , L = 17/w
larger: A = Lw =+2%2817%2Fw%29%282w%29 = 68cm^2