SOLUTION: Mark works out for 50 minutes by biking and jogging. He bikes at an average rate of 1200 feet per minute and jogs at an average rate of 900 feet per minute. He wants to travel a

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Question 903894: Mark works out for 50 minutes by biking and jogging. He bikes at an average rate of 1200 feet per minute and jogs at an average rate of 900 feet per minute. He wants to travel a combined 10 miles (1 mile = 5280 feet). How many minutes did Mark spend jogging?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
RT=D rate time distance

The question should be an accounting of distance. Also account for time.

T=D/R;

Let x = minutes biking
Let y = minutes jogging

1200%2Ax%2B900%2Ay=10%2Amiles%2A5280%28feet%2Fmile%29
AND
x%2By=50

Simplify the distance sum:
12x%2B9y=528
products of 3,...
4x%2B3y=176

The system to solve is then,
highlight%28system%284x%2B3y=176%2Cx%2By=50%29%29.