SOLUTION: The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
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Question 903883: The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let width be x
length = 2x+4
diagonal = 2x+6
x^2+(2x+4)^2= (2x+6)^2
x^2+4x^2+16x+16 = 4x^2+24x+36
x^2-8x-20=0
x^2-10x+2x-20=0
x(x-10)+2(x-10)=0
(x-10)(x+2)=0
x=10 ignore negative
width 10 inches
length = 24 inches
