SOLUTION: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice?
The amount of 90% orange juice
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The amount of 90% orange juice
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Question 903845: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice?
The amount of 90% orange juice is __ gallons? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! 0.9*x+0.3*16=0.5(16+x)
0.9*x+4.8=8+0.5x
0.9x-0.5x=8-4.8
0.4x=3.2
x=8 gallons of 90% is added to 16 gallons of 30% to get 24 gallons at 50%
check
0.9*8+0.3*16=0.5(16+8)
7.2+4.8=0.5(24)
12=12
ok
