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| Question 903801:  A basketball team sells tickets that cost $10, $20, or, for VIP seats, $30. The team has sold 545 tickets overall. It has sold 163 more $20 tickets than $10 tickets. The total sales are $9770. How many tickets of each kind have been sold?
 Answer by richwmiller(17219)
      (Show Source): 
You can put this solution on YOUR website! a+b+c=545, 10*a+20*b+30*c=9770,
 b=a+163
 a-b+0=-163
 1,1,1,545
 10,20,30,9770
 1,-1,0,-163
 
 (165,328,52)
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