SOLUTION: A TEST INVOLVING ONE POPULATION PROPORTION: a recent article in USA today reported that job awaits only one in three new college graduates. the major reasons given were an overabu

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Question 903679: A TEST INVOLVING ONE POPULATION PROPORTION:
a recent article in USA today reported that job awaits only one in three new college graduates. the major reasons given were an overabundance of college graduates and a weak economy. A survey of 200 recent graduates from your school revealed that 80 students had jobs. at the .02 significant level we can conclude that a larger proportion of graduates at your school have jobs?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Ho: p = .33
Ha: p > .33 (claim)
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sample proportion = p-hat = 80/200 = 2/5 = .4
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test stat:: z(x > .4) = (0.4-0.33)/sqrt[(1/3)(2/3)/200] = .07/.03= 2.33
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p-value = P(z > 2.33) = 1 - P( Z < 2.33) = 1 - .99 = .01
Since the p-value is less than .02, reject Ho.
The test results support the claim.