SOLUTION: 1. The sum of three consecutive odd integers is 57. What is the sum if each of the numbers is doubled? a.108 b.110 c.112 d.114 e.116 2.four times a number added to 8 gives

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: 1. The sum of three consecutive odd integers is 57. What is the sum if each of the numbers is doubled? a.108 b.110 c.112 d.114 e.116 2.four times a number added to 8 gives       Log On


   

Question 903656: 1. The sum of three consecutive odd integers is 57. What is the sum if each of the numbers is doubled?
a.108
b.110
c.112
d.114
e.116
2.four times a number added to 8 gives 20. What is the number?
a.3
b.6
c.9
d.12
e.15
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
I would logically guess, 114, without trying to do algebra in symbols and equation.

2n+1, 2n+3, 2n+5.
Their sum 2n%2B1%2B2n%2B3%2B2n%2B5=57
6n%2B9=57
6n=48
n=48%2F6
n=8

The original numbers would be 17, 19, 21.

NOW, if those are doubled and then summed:
2%2817%2B19%2B21%29
2%2A57
highlight%28114%29