SOLUTION: Two runners live 33 miles apart. Jim runs 8 miles per hour, and Joan runs 6 miles per hour. If Joan starts running toward Jim’s house and Jim starts running toward Joan’s house 2 h

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Question 903537: Two runners live 33 miles apart. Jim runs 8 miles per hour, and Joan runs 6 miles per hour. If Joan starts running toward Jim’s house and Jim starts running toward Joan’s house 2 hours later, how long will Jim have been running when they meet?
Found 2 solutions by josmiceli, lwsshak3:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Find Joan's head start
Let +d%5B1%5D+ = Joan's head start
+d%5B1%5D+=+6%2A2+
+d%5B1%5D+=+12+
---------------
Start a stop watch when Jim starts running
Let +d+ = distance Jim travels until they meet
Let +t+ = time in hrs until they meet
-----------------------------------
Jim's equation:
(1) +d+=+8t+
Joan's equation:
(2) +33+-+12+-+d+=+6t+
------------------------
Substitute (1) into (2)
(2) +33+-+12+-+8t+=+6t+
(2) +14t+=+21+
(2) +t+=+3%2F2+
Jim runs for 1 hr and 30 min until they meet
------------------
check:
(1) +d+=+8%2A%283%2F2%29+
(1) +d+=+12+
and
(2) +33+-+12+-+d+=+6%2A%283%2F2%29+
(2) +21+-+d+=+9+
(2) +d+=+12+
OK


Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Two runners live 33 miles apart. Jim runs 8 miles per hour, and Joan runs 6 miles per hour. If Joan starts running toward Jim’s house and Jim starts running toward Joan’s house 2 hours later, how long will Jim have been running when they meet?
***
let x=Jim's travel time
x+2=Joan's travel time
distance=speed*travel time
..
6(x+2)+8x=33
6x+12+8x=33
14x=21
x=21/14=3.5
how long will Jim have been running when they meet? 3.5 hrs