SOLUTION: With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of th
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-> SOLUTION: With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of th
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Question 903534: With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of the current. What is the rate of the canoe in still water? Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! With the current, you can canoe 104 miles in 4 hours. Against the same current, you can canoe only 3/4 of this distance in 6 Hours. Find your rate in still water and the rate of the current. What is the rate of the canoe in still water?
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let x=rate of canoe in still water
let c=rate of current
x+c=rate of canoe with current
x-c=rate of canoe against current
travel time*rate=distance
..
4(x+c)=104
6(x-c)=(3/4)*104=78
..
4x+4c=104
6x-6c=78
..
12x+12c=312 (mult. by 3)
12x-12c=156 (mult. by 2)
add
24x=468
x=19.5
4c=104-4x=26
c=6.5
rate of canoe in still water=19.5 mph
rate of current=6.5 mph
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