SOLUTION: Two cyclists leave towns 90mi apart at the same time and travel toward each other. One cyclist travels 8 /mih faster than the other. If they meet in 3 hours, what is the rate of

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Question 903490: Two cyclists leave towns 90mi apart at the same time and travel toward each other. One cyclist travels 8 /mih faster than the other. If they meet in 3 hours, what is the rate of each cyclist?
Found 2 solutions by richwmiller, Edwin McCravy:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Do not spread out your problems to take up more space.
They are also harder to read.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
What a grouch!

Two cyclists leave towns 90mi apart at the same time and travel toward each
other. One cyclist travels 8 mph faster than the other. If they meet in 3
hours, what is the rate of each cyclist?
                rate  •  time = distance   
slower cyclist    x       3        3x
faster cyclist   x+8      3      3(x+8)

The sum of their distances must equal the total distance they were
apart when they started.

            3x + 3(x+8) = 90
           3x + 3x + 24 = 90 
                6x + 24 = 90
                     8x = 66
                      x = 66%2F8=8.25mph

The slower cyclist was going 8.25 mph and the faster one was going
8 mph faster or 16.25 mph.

Edwin